Question

g(x)=x-2 , p(x)=x⁴-x³-x²-x-2 ...Solve it by factor theorem​

Answer 1

give X - 2 = 0

X= 2

substitute 2 in place of x

X4 - X3 - X2 - X - 2

16- 8- 4 -2 -2

16 -12-4

16-16

0

when the remainder is zero the the g (x) is the factor of the equation .

therefore x- 2 is the factor of X4 - X3 - X2 - X - 2

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