Question

7. The perimeter of a rectangle is 130 cm. If the breadth of the rectangle is
30 cm, find its length. Also find the area of the rectangle.
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Answer 1

PERIMETER OF RECTANGLE IS 2(L + B)

2(L + 30)= 130

2L + 60 = 130

2L = 130 - 60 = 70

L = 70/2 = 35

AREA = L×B

35 × 30 = 1050 cm².

hope it helps u.

Answer 2

$\huge \sf \underline \red{Answer : }$

$\sf \underline \green{ \therefore \: length \: of \: rectangle = 30cm}$

$\sf \underline \green{ \therefore \: Area \: of \: rectangle = 1050 {cm}^{2} }$

$\huge \sf \underline \orange{Given : }$

• Perimeter of rectangle is 130cm

• breadth of rectangle is 30cm

$\sf \huge \underline \pink{To \: find : }$

• Length

• Area of rectangle

$\huge \sf \underline \blue{solution : }$

$\sf \underline{length \: of \: rectangle \: be \: l}$

$\sf \underline{breadth \: of \: rectangle = 30cm}$

$\sf \star \: \underline{we \: know \: that : }$

$\sf{ \boxed{ \underline{ \underline{ \red{ \tt{Perimeter \: of \: rectangle = 2(l + b) \: }}}}}}$

where,

• length = l

• breadth = 30cm

• perimeter of rectangle = 130cm

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{2(l + b) = 130cm}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{2(l + 30) = 130cm}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{l + 30 = \dfrac{130}{2}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{l + 30 = 65}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{l = 65 - 30}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{l = 35cm}$

$\sf \underline \green{ \therefore \: length \: of \: rectangle = 30cm}$

$\sf \star \: \underline{Now \: we \: have \: to \: find \: Area \: of \: triangle : }$

$\sf \star \: \underline{we \: know \: that : }$

$\: \: \: \: \: \sf{ \boxed{ \underline{ \underline{ \red{ \sf{Area\: of \: rectangle = l \times b \: }}}}}}$

where,

• length = 35cm

• breadth = 30cm

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{35 \times 30}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{1050sq.cm}$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{1050 {cm}^{2}}$

$\sf \underline \green{ \therefore \: Area \: of \: rectangle = 1050 {cm}^{2} }$