708 km distance an express train 6h more than rajdhani train take if express train speed is double the express train time 3h taken less than rajdhani so find speed of rajdhani exp
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let rajdhani's speed be y, expess' speed be x
time= distance/speed
difference in time in condition 1:
(708/x)-(708/y)=6
condition 2:
(708/y)-(708/(2x))=3
adding both the equations,
(708/x)-(708/y)+(708/y)-708/(2x))=9
implies (708/x)-(354/x)=9
x= 118/3 kmph
applying x in solution 1,
y = 59 kmph.
time= distance/speed
difference in time in condition 1:
(708/x)-(708/y)=6
condition 2:
(708/y)-(708/(2x))=3
adding both the equations,
(708/x)-(708/y)+(708/y)-708/(2x))=9
implies (708/x)-(354/x)=9
x= 118/3 kmph
applying x in solution 1,
y = 59 kmph.
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