Question

7x_3y_31=0//9x_5y_41=0

Answer 1

7x - 3y - 31 = 0 1.)

9x - 5y - 41 =0 2.)


By using elimination method..

63x - 27y - 279 = 0
63x - 35y - 287 = 0
- + +
_____________
8y + 8 = 0

8y = - 8
y = -1

Put the value of y in equation 1.)

7x - 3(-1) - 31 = 0
7x + 3 - 31 =0
7x -28 = 0
7x = 28
x = 4



So that the value of x and y is 4 and -1 respectively...

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#Hope its help you#
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