Question

7x+3y=5 ; 2x-9y=6in in simultaneous eqaution ​

Answer 1

1st equation

$7x + 3y = 5 \: \: (\times 3)$

2nd equation

$2x - 9y = 6$

Now,

$21x + 9y = 15$

$2x - 9y =6$

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$23x = 21$

$x = \frac{21}{23}$

Putting value of x in equation 2

$2( \frac{21}{23} ) - 9y = 6$

$\frac{42}{23} - 9y = 6$

$- 9y = 6 - \frac{42}{23}$

$- 9y = \frac{138 - 42}{23}$

$- 9y = \frac{96}{23}$

$y = \frac{96}{23} \times \frac{ - 1}{9}$

$y = \frac{ - 96}{207}$