Math, asked by vibha200712, 3 months ago

8^2x=1/64
find the value of x

Answers

Answered by NewGeneEinstein
0

\\ \sf\hookrightarrow 8^{2x}=\dfrac{1}{64}

\\ \sf\hookrightarrow 8^{2x}=\dfrac{1}{8^2}

\\ \sf\hookrightarrow 8^{2x}=8^{-2}

\\ \sf\hookrightarrow 2x=-2

\\ \sf\hookrightarrow x=\dfrac{-2}{2}

\\ \sf\hookrightarrow x=-1

Answered by mdshariqulhaque600
0

Explanation:

8^2x= 1/64

8^2x= 8^-2

  • if the power is equal then base is also equal

2x= -2

x= -1

Final Answer:

the value of x is -1

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