Question

(8+4x)^3 jldi btao or with identity ke sath​

Answer 1

We have,

$\quad \: {(4x + 8)}^{3} \\ \\ = {(4(x + 2))}^{3} \\ \\ = 64 {(x + 2)}^{3} \\ \\ = 64( {(x)}^{3} + {(2)}^{3} + 3(x)(2)(x + 2)) \\ \\ = 64( {x}^{3} + 8 + 6 {x}^{2} + 12x) \\ \\ = 64( {x}^{3} + 6 {x}^{2} + 12x + 8) \\ \\ = 64 {x}^{3} + 384 {x}^{2} + 768x + 512$

Identity Used :—
$\underline{\boxed{\sf{ {(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b)}}}$

Answer 2

$Answer :$

$(8 + {4x})^{3} \\ {12}^{3} \\ 12 \times 12 \times 12 = 1728$

$mark \: as \: brainliest$