Question

8. A, B and C can do a piece of work in 15, 12 and 20 days respectively. They started the work together,
but C left after 2 days. In how many days will the remaining work be completed by A and B?​

Answer 1

2 day work of A+B+C=24

Work left=36

A+b=9

Remaining work will be completed in =36/9=4 days

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Answer 2

Answer:

4 Days

Step-by-step explanation:

Work is done by A in one day =  1/15

By B= 1/12

C= 1/20

Together in 1 Day = 1/15 + 1/12 + 1/20 = 4+5+3/60 = 12/60 = 1/5

2 days work = 2/5

Remaining work = 1−  2/5 = 3/5

one day work of  A,B ⇒A+B= 1/5 + 1/12 = 4+5/60 = 9/60 = 3/20

(A+B) work for t days =  3/20 t = 3/5  t=4 days

A and B will complete the work in 4 days.

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