Question

8(a+b+c)³-(b+c)³-(c+a)³-(a+b)³​

Answer 1

Answer:

Open all brackets

a³+b³+3a²b +3ab²+b³+c³+3b²c +3bc²+c ³+a ³+3a²c+3ac²-3(abc+a²b+ac ²+a ²c+b ²c+b ²a+bc²+abc)

=2a³+2b³+2c³+3a²b+3 ab²+3 a²c+3 ac²+3bc²+3 b²c - 3a²b+3 ab²+3 a²c+3 ac²+3 b²c+3 bc²

=2a³+2b³+2c³-6abc

=2(a³+b³+c³+3abc)

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