Question

8. A player sitting on the top of a tower of height 20 m observe the angle of depression
of a ball lying on the ground as 60°. Find the distance between the foot of the tower
and ball
DINESH Let Media​

Answer 1

Answer:

this may be help yourself

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Distance\:between\:ball\:and\:foot\:of\:tower=20\sqrt{3}\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Height \: of \: tower = 20 \: m \\ \\ \tt: \implies Angle \: of \: elevation\:of\:ball = 30 \degree \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Distance \: between \: ball \: and \:foot \: of \: tower = ?$

• According to given question :

$\tt \circ \: \angle \: B = 60 \degree \\ \\ \tt \circ \: AC =20 \: m \\ \\ \bold{In \:right \: angled \: \triangle \: ABC} \\ \tt: \implies tan \: \theta = \frac{perpendicular}{base} \\ \\ \tt: \implies tan \: 30 \degree = \frac{AC}{CB} \\ \\ \tt \circ \: tan \: 30 \degree = \frac{1}{ \sqrt{3}} \\ \\ \tt: \implies \frac{1}{\sqrt{3}} = \frac{20}{CB} \\ \\ \green{\tt: \implies CB = 20\sqrt{3}\:m} \\ \\ \green{\tt \therefore Distance \: between \: ball \: and \: foot \: of \: tower \: is \: 20\sqrt{3}\: m}$