Question

8. Find x, if
3^x+1=1/(27)^x-3​

Answer 1

$3 ^{x + 1} = \frac{1}{27 ^{x - 3} } \\ {3}^{x + 1} = 27 ^{ - x + 3} \\ {3}^{x + 1} = 3^{3( - x + 3)} \\ 3^{x + 1} = 3 ^{ - 3x + 9} \\ x + 1 = - 3x + 9 \\ x + 3x = 9 - 1 \\ 4x = 8 \\ x = 2$