Question

factorize 8x²— 40x+50​

Answer 1

$8 {x}^{2} - 40x + 50 \\ 2(4 {x}^{2} - 20x + 25) \\ 2( {(2x)}^{2} - 2(2x)(5) + {(5)}^{2} ) \\ using \: identity \: {a}^{2} - 2ab + {b}^{2} = {(a - b)}^{2} \\ 2 {(2x - 5)}^{2} \\ 2(2x - 5)(2x - 5)$

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Answer 2

Answer:

8x²— 40x+50​  = (2x-5)(4x-10)

Step-by-step explanation:

8x²— 40x+50​ = 8x²-20x-20x+50

                        = 4x(2x-5)-10(2x-5)

                        = (2x-5)(4x-10)

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