Question

8 ) If a = 2 +
$\sqrt{13}$
13, then find the value of a -1/a​

Answer 1

Answer:

$a = 2 + \sqrt{13} \\ \\ \frac{a + 1}{a} \\ = \frac{2 + \sqrt{13} + 1 }{2 + \sqrt{13} } \\ = \frac{3 + \sqrt{13} }{2 + \sqrt{13} } \\ = \frac{(3 + \sqrt{13} )(2 - \sqrt{13} )}{(2 + \sqrt{13})(2 - \sqrt{13}) } \\ = \frac{6 - 3 \sqrt{13} + 2 \sqrt{13} - 13}{4 \: - 13} \\ = \frac{ - 7 - \sqrt{13} }{ - 9} \\ = \frac{7 + \sqrt{13} }{9}$

Hope it helps

Answer 2

Step-by-step explanation:

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