Math, asked by Sevyasahasra, 6 months ago

8.lf a+b+=5 and ab+bc+ca=10 then the value of a^3+b^3+c^3-3abc=.......​

Answers

Answered by Alishasheikh1108
0

a+B+C =to 24 by 5  

hope it helps you i think its wrong or correct

Answered by rishavtoppo
2

We Know

3 a + b + c3 -3abc = ( a + b + c ) ( a² + b² + c² -ab - bc - ca )

now,

a + b + c = 5

ab + bc + ca = 10

( a + b + c ) 2 = a² + b² + c² +2 ( ab + bc + ca )

( 5 ) 2 -2x10 = a² + b² + c²

a² + b² + c² = 5

hence ,

a³ + b³ + c³ -3abc = ( a + b + c ) ( a + b + c² -ab - bc - ca )

= ( 5 ) ( 5 - 10 ) = 5 × ( -5 ) = -25

why are you replying in my mesage please reply it

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