Question

sum of two numbers is 74. one of the number is ten more than the another construct expresions​

Answer 1

Given :

• Sum of 2 numbers = 74
• One of the number is 10 more than the other.

To Find :

• equations for the given situation

Solution :

Let, the two numbers be x and y.

According to the problem,

x + y = 74

x = y + 10

Answer 2

Step-by-step explanation:

${ \mapsto{ \orange{let \: the \: numbers \: be \: x \: and \: y}}} \\ { \bold{ \pink{ \mathbb{case \: 1 : }}}} \\ sum \: of \: the \: numbers \: is \: 74 \\ x + y = 74.........(1) \\ { \bold{ \pink{ \mathbb{case \: 2 : }}}} \\ one \: number \: is \: 10 \: more \: than \: the \: other \: \\ let \: y \: be \: the \: smaller \: number \: then \\ x = 10 + y \\ x - y = 10.......(2) \\ \bf{ \bold{ \mathbb{ \blue{ \: 1 \: and \: 2 \: are \: the \: required \: equations}}}} \\ by \: simplifying \: 1 \: and \: 2 \: we \: get \\ { \mapsto{x + y + x - y = 74 + 10}} \: \: \: (adding \: two \: equations) \\ { \mapsto{2x = 84}} \\ { \mapsto{ \orange{\boxed{ \mathbb{x = 42}}}}} \\ x \: in \: eqn \: 1 \\ { \mapsto{ 42 + y = 74}} \\ { \mapsto{ y = 74 - 42}} \\ { \mapsto{ \orange {\boxed{ \mathbb{y = 32}}}}}$

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