8 molar;1.5ml hno3 aqoues solution.find out mass of hno3 present in solution.
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Hello!
We have the following data:
M (molarity or Molar Concentration) = 8 Molar (Mol/L)
m1 (mass of the solute HNO3) = ? (in grams)
V (volume) = 1.5 mL → 0.0015 L
MM (molar mass of HNO3)
H = 1*1 = 1 u
N = 1*14 = 14 u
O = 3*16 = 48 u
----------------------
MM (molar mass of HNO3) = 1 + 14 + 48 = 63 g/mol
We apply the data to the molar concentration formula, see:





I Hope this helps, greetings ... DexteR!
We have the following data:
M (molarity or Molar Concentration) = 8 Molar (Mol/L)
m1 (mass of the solute HNO3) = ? (in grams)
V (volume) = 1.5 mL → 0.0015 L
MM (molar mass of HNO3)
H = 1*1 = 1 u
N = 1*14 = 14 u
O = 3*16 = 48 u
----------------------
MM (molar mass of HNO3) = 1 + 14 + 48 = 63 g/mol
We apply the data to the molar concentration formula, see:
I Hope this helps, greetings ... DexteR!
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