8 urgently only genius can solve this
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A=100sq.cm
A=1/2 bh
given that right angled isosceles triangle
so b=h
1/2 b^2=100
b^2=200
b=√200
b=10√2=h
according to Pythagoras theorem
a^2+b^2=c^2
here a=b=10√2
(10√2)^2+(10√2)^2=c^2
200+200=c^2
c^2=400
c=√400=20
perimeter of an isosceles triangle=2×equal side+third side
=2×10√2+20
=20√2+20
=20(√2+1) cm
A=1/2 bh
given that right angled isosceles triangle
so b=h
1/2 b^2=100
b^2=200
b=√200
b=10√2=h
according to Pythagoras theorem
a^2+b^2=c^2
here a=b=10√2
(10√2)^2+(10√2)^2=c^2
200+200=c^2
c^2=400
c=√400=20
perimeter of an isosceles triangle=2×equal side+third side
=2×10√2+20
=20√2+20
=20(√2+1) cm
hemanth2261:
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