Question

80 gram of water at 30 degree celsius is poured on a large block of ice at zero degree Celsius the mass of ice that melt is​

Answer 1

Answer:

Explanation:

Heat gained by the melting ice, mL = heat given by the water, mcΔt  

mL = mcΔt  

m x 334 = 80 x 4.18 x (30 - 0)  

334 m = 10032  

m = 10032/ 334 = 30.04