840 logs of wood are placed in 7 rows
one above the others The bottom row
consists of maximum dogs. Each of the
subsequent rows consists of 30 logs less
than the previous row. Find the number of logs in each row.
Answers
Answered by
10
Answer:
210,180,150,120,90,60,30.
Step-by-step explanation:
Let the number of logs in first row be = x
No. of rows = 7
Difference in logs of each row = (-30)
This becomes an arithmetic progression,
where a = x ; d = (-30) ; n = 7 ; Sₙ = 840
Now by using the formula for finding the sum of 'n' terms of an A.P., we get,
Sₙ = n/2 x {2a + (n-1)d}
840 = 7/2 x {2x + 6(-30)}
840(2)/7 = 2x - 180
(240 + 180)/2 = x
210 = x
Hence the number of loge in each row were 210,180,150,120,90,60,30.
Hope it helps you....
Answered by
72
AnswEr :
Let the Number of Logs in Top Row be 30. & as there is Maximum Logs in Bottom Row, then we will Add the Common Difference i.e. 30 here.
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