Question

85. The molecular weight of O, and SO2 are 32 and
64 respectively. At 15°C and 150 mmHg
pressure, one litre of O, contains N' molecules.
The number of molecules in two litres of SO,
under the same conditions of temperature and
pressure will be
(a) 1/2
(b) N
(c) 2N
(d) 4V​

Answer 1

Answer:

it has 2N no of molecules

Explanation:

vol of oxygen÷no of molecules of oxygen=vol of so2÷no of molecules so2

Answer 2

SoluTion :-

$\sf {Given :-}\\\\\\\sf{T = 15^o C}\\\\\sf{P = 759\ mm}\\\\\\\sf{Volume\ of\ O_2 = V_1 = 1\ Lit}\\\\\sf{No.\ of\ molecules\ of\ O_2=n_1 = N}\\\\\sf {Volume\ of\ SO_2 =V_2 = 2\ Lit}\\\\\sf {No.\ of\ molecules\ of\ SO_2=n_2 =?}$

$\sf {Formula : \boxed {\frac{V_1}{N_1} = \frac{V_2}{N_2}} ....Avogadro's\ law}\\\\\\\\\sf {\frac{1}{N}=\frac{2n}{2} }\\\\\sf {Hence,\ n_2 = 2N}\\\\\\\sf {Answer= (c)\ 2N}$