8a-b2=24
And
8b+b2=56
Then
a+b=?
I need this answer
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Given: Two equations 8a - b^2 = 24 and 8b + b^2 = 56
To find: The value of a + b?
Solution:
- Now we have given two equation:
8a - b^2 = 24 ............(i)
8b + b^2 = 56 ............(ii)
- From (i), we get:
8a - 24 = b^2
- Putting this value of b^2 in (ii), we get:
8b + 8a - 24 = 56
- Now solving this, we get:
8b + 8a = 56 + 24
- Taking 8 common, we get:
8(a + b) = 80
a + b = 80/8
a + b = 10
Answer:
So the value of a + b is 10.
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