Question

8x+3y=2, y+3z=7, 2x+2z=8.​

Answer 1

Step-by-step explanation:

Given:

8x + 3y = 2, y + 3z = 7, 2x + 2z = 8

To find:

Solve by Cramer's rule.

Solution:

From the given information, we have the data as follows.

8x + 3y = 2, y + 3z = 7, 2x + 2z = 8

We are asked to solve these equations using Cramer's rule.

Write the given equations in terms of matrix.

8 3 0

0 1 3

2 0 2

⇒ Δ = 34

Now compute Δ₁

2 3 0

7 1 3

8 0 2

⇒ Δ₁ = 34

Now compute Δ₂

8 2 0

0 7 3

2 8 2

⇒ Δ₂ = -68

Now compute Δ₃

8 3 2

0 1 7

2 0 8

⇒ Δ₃ = 102

Now, we will solve for the variables.

x = Δ₁/Δ

x = 34/34

x = 1

y = Δ₂/Δ

y = -68/34

y = -2

z = Δ₃/Δ

z = 102/34

z = 3

Therefore, the values are x = 1, y = -2 and z = 3