Question

8x+5y-11=0,3x-4y-10=0

Answer 1

$8x + 5y - 11 = 0......1 \\ 3x - 4y - 10 = 0......2 \\ from \: 1 \: we \: get \\ x = \frac{11 + 4y}{8} \\ subsituting \: the \: value \: of \: x \: in \: (2) \: we \: get \\ 3( \frac{11 + 4y}{8} ) - 4y - 10 = 0 \\ \frac{33 + 12y - 32y - 80}{8} = 0 \\ - 20y - 47 = 0 \\ y = - \frac{47}{20} \\ subsituting \: y \: in \: (2) \: we \: get \\ 3x - 4( - \frac{47}{20} ) - 10 = 0 \\ 3x + \frac{47}{5} - 10 = 0 \\ \frac{15x + 47 - 50}{5} = 0 \\ 15x = 3 \\ x = \frac{3}{15} \\ x = \frac{1}{5}$