8x+5y=9,kx+10y=15 has a unique solution .
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Answered by
7
Answer:
heya
here is ur answer
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given :-
8x + 5y = 9
kx + 10y = 15
Transposing to RHS
8x+5y-9=0
kx+10y-15=0
✴ they has a unique solution ( given)
so they are intersecting lines.
a1/a2 not is equal to b1/b2 not is equal to c1/c2
a1/a2 ≠ b1/b2 ≠ c1/c2
➡ 8/k ≠ 5/10 ≠ -9/-15
➡8/k ≠ 5/10
➡8/k ≠ 1/2
➡k ≠ 8*2
➡k ≠ 16
k can have all values except 16.
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hope it helps u..!!
Answered by
2
Yes it has a unique solution
Hope it helps u
Plsss mark it as brainliest
Hope it helps u
Plsss mark it as brainliest
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