(9/7)^3 x (49/81)^2x-16 = (7/9)^9 what js the value of x
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(7/9)^-3*(7/9)^2(2x-16)=(7/9)^9
(7/9)^-3*(7/9)^4x-64=(7/9)^9
comparing powers as bases are equal
-3+4x-64=9
4x-67=9
4x=9+67
4x=76
x=76/4
x=19
(7/9)^-3*(7/9)^4x-64=(7/9)^9
comparing powers as bases are equal
-3+4x-64=9
4x-67=9
4x=9+67
4x=76
x=76/4
x=19
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