9.8 grams of H2 S o4 is present in 2 litre of solution the molarity of the solution is
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Molecular mass of H2SO4=98g
No. of moles of H2SO4 present=9.8/98
=0.1moles
Molarity=No. of moles of solute/ Volume of solvent in litres
=0.1/2
=0.05M
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