9. Find the altitude of a trapezium whose area
is 105 cm2 and whose bases are 14 cm and
7 cm.
Answers
Answered by
1
Answer:
Given: Area of the trapezium=65 cm2
The lengths of the opposite parallel sides are 13 cm and 26 cm.
Area of trapezium=12×(Sum of parallel bases)×(Altitude)
On putting the values: 65=12×(13+26)×(Altitude)65×2=39×AltitudeAltitude=13039=103 cm
Step-by-step explanation:
Answered by
1
Answer:
altitude 2.5cm
Step-by-step explanation:
area of trapezium = 1/2 (a+)h
105 = 1/2 ( 14+7 )h
105/2 = (21)h
105/42 = h
h = 2.5cm
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