Question

9. Find the coordinates of the point p which divides the join of a(-2,5) and b(3,-5) in the ratio

Answer 1

Complete Question : Find the coordinates of the point p which divides the join of a(-2,5) and b(3,-5) in the ratio “2:3”.

Section formula

$\mathsf{x = \frac{mx_2 + nx_1}{m + n}, y = \frac{my_2 + ny_1}{m + n}}$

• m and n are parts
• $\mathsf{x_1,x_2,y_1\:and\:y_2}$ are coordinate values
• x and y are point dividing value.

______________________________

The m and n parts of our point ‘p’ are 2 and 3 respectively.

→ x = (2×3 - 3×2)/(2 + 3)

→ x = (6-6)/5

→ x = 0

→ y = (- 2×5 + 3×5)/(2 + 3)

→ y = (- 10 + 15)/5

→ y = 1

Coordinate ‘p’ = (0,1)

Answer 2

Answer

-2,5 and 3,-5 are in the ratio

$2:3$

m1,m2

$\x=mx²+nx1$

$\y=nmy²ny$

{M+N}

Considering m and n

Considering m and n Take x1,x2 and y1 ,y2

Considering m and n Take x1,x2 and y1 ,y2values are x and y

Steps

Value of X

x = (2×3 - 3×2)/(2 + 3)

x = (6-6)/5

x = 0

Value of Y

y = (- 2×5 + 3×5)/(2 + 3)

y = (- 10 + 15)/5

y = 1

$hence \: x = 0 \: and \: y = 1$