Question

9. Find three consecutive numbers such that four times the first plus twice the second minus five times the third number is zero.​

Answer 1

Answer:

Step-by-step explanation:

Let the three numbers be

x , x+1 , x+2

According to question

4x + 2 (x+1) - 5 (x+2) = 0

4x + 2x +2 - 5x - 10 = 0

6x - 5x - 8 = 0

x = 8

First no. = 8

Second no. = 8+1 = 9

Third no. = 8+2 = 10

Regards...............

Answer 2

Answer:

hi

Step-by-step explanation:

here is the answer