Subtract
Z^2-y^2+2yz from2z^2+3y^2-6yz
Answers
Answered by
5
Given, two polynomial , z² - y² + 2yz and 2z² + 3y² -6yz
Let P = z² - y² + 2yz and Q = 2z² + 3y² - 6yz
now, we have to subtract P from Q
e.g., Q - P = (2z² + 3y² - 6yz) - (z² - y² + 2yz)
= 2z² + 3y² - 6yz - z² + y² - 2yz
= (2 - 1)z² + (3 +1)y² -(6 + 2)yz
= z² + 4y² - 8yz
hence, answer should be z² + 4y² - 8yz
Let P = z² - y² + 2yz and Q = 2z² + 3y² - 6yz
now, we have to subtract P from Q
e.g., Q - P = (2z² + 3y² - 6yz) - (z² - y² + 2yz)
= 2z² + 3y² - 6yz - z² + y² - 2yz
= (2 - 1)z² + (3 +1)y² -(6 + 2)yz
= z² + 4y² - 8yz
hence, answer should be z² + 4y² - 8yz
Answered by
3
HELLO DEAR,
GIVEN:-
z² - y² + 2yz and 2z² + 3y² -6yz
Let A = z² - y² + 2yz and B = 2z² + 3y² - 6yz
now, we have to subtract A from B
B - A = (2z² + 3y² - 6yz) - (z² - y² + 2yz)
= 2z² + 3y² - 6yz - z² + y² - 2yz
= (2 - 1)z² + (3 +1)y² -(6 + 2)yz
= z² + 4y² - 8yz
HENCE, answer is z² + 4y² - 8yz
I HOPE ITS HELP YOU DEAR,
THANKS
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