Question

9 sec²A + 9 Tan²A=?
Correct Answer will be marked Brainliest​

Answer 1

Answer:

9 sec²A + 9 Tan²A=

9( sec²A + tan²A )

9( 1+tan²A+tan²A )                   [ since sec²x - tan²x =1]

9( 1+2tan²A)    

9 + 18tan²A  OR 18sec²A - 9       [ since sec²x - tan²x =1]

Answer 2

Answer:

9

Step-by-step explanation:

9 sec²A + 9 Tan²A

= 9(sec²A + Tan²A)

=9(sec²A + (sec²A-1)) [tan^2 A= Sin^2 A- 1]

=9(1)

=9