9 second square A - 9 tan square A
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it is sec2 my friend not second square
here goes the answer............
9 sec2 a - 9 tan2 a
9 can be taken as common
9(sec2a - tan2a)
we know that from the identity sec2 a - tan2 a is 1
so 9(1)
= 9
therefore the value of 9 sec2a - 9 tan2 a = 9
plz mark my answer as brainliest
it would be helpful
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