9. The perimeter of an isosceles triangle is 32 cm. The ratio of one of the
equal sides to its base is 3:2. Find the area of the triangle
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given that one of equal side to its base ratio is 3:2
so equal sides + base =perimeter
3x+2x +3x=32
x=32/8 =4
so sides are 12,12,8
s=(a+b+c)/2 =32/2 =16
we know that area of any triangle is
√s(s-a)(s-b)(s-c)
apply s,a,b,c sides in it u get 32√2 as answer
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Bharadwaj981:
2*4 =8 bro u write it unfortunately as 6
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