Question

if 3^(2n-1)=1/27^(n-3), then find the value of n..

ANSWER IT WITHOUT SPAMMING>>>>>>>

Answer 1

this is the answer according to your question. HOPE IT WAS OF SOME HELP AND IF YES THEN PLEASE FOLLOW AND LEAVE A COMMENT

Answer 2

The value of n = 2

Given :

$\displaystyle \sf {3}^{(2n - 1)} = \frac{1}{ {27}^{(n - 3)} }$

To find :

The value of n

Solution :

Step 1 of 2 :

Write down the given equation

Here the given equation is

$\displaystyle \sf {3}^{(2n - 1)} = \frac{1}{ {27}^{(n - 3)} }$

Step 2 of 2 :

Find the value of n

$\displaystyle \sf {3}^{(2n - 1)} = \frac{1}{ {27}^{(n - 3)} }$

$\displaystyle \sf{ \implies }{3}^{(2n - 1)} = \frac{1}{ { ({3}^{3}) }^{(n - 3)} }$

$\displaystyle \sf{ \implies }{3}^{(2n - 1)} = \frac{1}{ {3}^{ \{3(n - 3) \}} }$

$\displaystyle \sf{ \implies }{3}^{(2n - 1)} = \frac{1}{ {3}^{(3n - 9) } }$

$\displaystyle \sf{ \implies }{3}^{(2n - 1)} = {3}^{ \{( - 1) \times (3n - 9) \}}$

$\displaystyle \sf{ \implies }{3}^{(2n - 1)} = {3}^{ (9 - 3n)}$

$\displaystyle \sf{ \implies }2n - 1 = 9 - 3n$

$\displaystyle \sf{ \implies }5n = 10$

$\displaystyle \sf{ \implies }n = \frac{10}{5}$

$\displaystyle \sf{ \implies }n = 2$

Hence the required value of n = 2

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ choose the correct alternative : 100¹⁰⁰ is equal to (a) 2¹⁰⁰ × 50¹⁰⁰ (b) 2¹⁰⁰ + 50¹⁰⁰ (c) 2² × 50⁵⁰ (d) 2² + 50⁵⁰

https://brainly.in/question/47883149

2. Using law of exponents, simplify (5²)³÷5³

https://brainly.in/question/36250730

#SPJ2