Question

9. The Ph of a solution of HCL is 4. This shows that the molarity of the solution is (a) 4.0M (b) 0.4M (c) 0.0001M (d) 0.001M

Answer 1

pH = - log [H+]
4 = - log [H+]
[H+] = 10^(-4)
[H+] = 0.0001

Here molarity of the solution will be equal to concentration of 1 × [H+] because there is only one H+ ion and one Cl- ion

(c) 0.0001M

Hope this helps.... plsss make it the brainliest

Answer 2

The correct option is c.

Given: The pH of a solution of HCL is 4.

To find: We have to find the molarity of the solution.

Solution:

The molarity of HCl is defined in terms of the concentration of hydrogen ions.

Now we know that,

$pH=-log[H^+]$

Given pH is 4.

Let concentration of hydrogen ion is x.

Thus we can write-

$4 = - logx \\ x = {10}^{ - 4} \\ x = 0.0001$

The molarity of the solution is 0.0001M.