9 years ago,the average age of a family of five members was 33 years. Now, three new members join whose agesare in ascending order with consecutive gaps of 8 years. If the present average age ofthe family is the same as it was 9 years ago, whatis the age (in years) of the youngest new member ?
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average age of family = 33
sum of ages of five family 9 years ago = 33*5 = 165 years
sum of present age of 5 members = 165-9*5=165-45=120
let the age of younger member be x yrs second member x+8 and other x+16
120+3x+24 = 165
144+3x= 165
3x=21
x=7
hence, the age of younger age of studen
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