Question

90% of first order process X----->Y is completed in a time equals to 99% of another first order process Y------>Q. If K value of Y----->Q is 0.09 sec^1, K value of X------->Y will be.

Answer 1

k=0.00450sec^-1......

Answer 2

Answer:

The answer is 0.045 sec⁻¹.

Explanation:

The reaction in which the rate is proportional to the concentration of the reactant is known as a first-order reaction.

The formula of the rate constant of a first-order reaction is

  $K = \frac{2.303}{t} log\frac{R'}{R}$

where R' is the initial concentration and R is the current concentration of the reactant.

1) In X to Y reaction

$t1 = \frac{2.303}{K1}log\frac{100}{10}$

2) In Y to Q

$t2 = \frac{2.303}{0.09}log\frac{100}{1}$

Equate equation 1 and 2,  

t₁ = t₂

$\frac{1}{K1} = \frac{2}{0.09}$

K₁ = 0.045 sec⁻¹

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