9x square - x -4 please solve this answer
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Finding the roots of 9x^2-x-4 is same as solving the equation 9x^2-x-4=0.
Thus, 9x^2-x-4=0
=> (3x)^2-(2×3x×1/6)+(1/6)^2-4-(1/6)^2=0
(Completing the square method)
=> (3x-1/6)^2-1/36-4=0
=> (3x-1/6)^2-(1/36+144/36)=0
=> (3x-1/6)^2-145/36=0
=> (3x-1/6)^2-(sqrt145/6)=0
=> (3x-1/6-sqrt145/6)(3x-1/6+sqrt145/6)=0
=> 3x-1/6-sqrt145/6=0 and 3x-1/6+sqrt145/6=0
=> x=(1+sqrt145)/18 or x=(1-sqrt145)/18
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