Question

9x2+6x+4=0 find the roots of quadratic formula​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Given :

$9 {x}^{2} + 6x + 4 = 0$

To Find :

Roots of given equation

Above equation is in the form of a quadratic equation so we factorise it and hence find roots.

We use quadratic formula for finding the roots :

Formula :

$\bold{\boxed{\red{\frac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a}}}}$

Here ,a=9 ; b=6 and c=4

$= > \frac{ - 6 ± \sqrt{ {(6)}^{2} - 4(9)(4)} }{2 \times 9}$

$= > \frac{ - 6 ± \sqrt{36 - 144} }{18}$

$= > \frac{ - 6 ± \sqrt{ - 108} }{18}$

=>Here ,this is negative inside root so,to remove negative sign we use 'i' (iota) in place of - sign.

$= > \frac{ - 6 ± \sqrt{108i} }{18}$

$= > \frac{3( - 2 ± \sqrt{36i}) }{18} = \bold{ \frac{ - 2 ± \sqrt{36i} }{6} }$