9xsq +6x+1 factorise using appropriate identity
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Hello dear
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given us that
9x² + 6x + 1
= 9x² + 3x + 3x + 1
= 3x ( 3x + 1 ) + 1 ( 3x + 1 )
= ( 3x + 1 ) ( 3x + 1 )
thanks
====================================
===================================
given us that
9x² + 6x + 1
= 9x² + 3x + 3x + 1
= 3x ( 3x + 1 ) + 1 ( 3x + 1 )
= ( 3x + 1 ) ( 3x + 1 )
thanks
====================================
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