Question

A 0.2076g sample of an oxide of cobalt on analysis was found to contain0. 1476g cobalt. Calculate the empirical formula of the oxide​

Answer 1

Answer:

The empirical formula of the Oxide of Cobalt is CoO

Explanation:

Step 1 : Calculate the mass of Oxygen in the compound.

Given the mass of Cobalt and the total mass of the Oxide we can get the mass of Oxygen.

Mass of Oxygen = 0.2076g - 0.1476g = 0.06 g

Step 2: Calculate the moles of Oxygen and Cobalt.

Molar mass of Cobalt = 59

Moles of Cobalt = 0.1476/59 = 0.002502 moles.

Molar mass of Oxygen = 16

Moles of Oxygen = 0.06/16 = 0.00375

Step 3 : Identify the smallest value of moles then divide by each mole.

The least is 0.002502 moles

Co = 0.002502/0. 002502 = 1

O = 0.002502/0.00375 = 1.4

Approximately 1.

Step 3 : Write down the Empirical formula of the Oxide.

Coo.

Answer 2

Explanation:

Calculate the mass of Oxygen in the compound. Given the mass of Cobalt and the total mass of the Oxide we can get the mass of Oxygen. Step 2: Calculate the moles of Oxygen and Cobalt. Moles of Cobalt = 0.1476/59 = 0.002502 moles.