Question

A 1.00 kg mass is placed at the free end of a compressed spring. The spring constant of the spring is 115 N/m. The spring has been compressed 0.200 m. How much potential energy is stored in the spring?

Answer 1

Explanation:

HEY MATE ..

We know that,

We know that,U= 2 /1 kx ^2

⇒U= 2/ 1 k(1) ^2 =1 /2 k

Total compression x =1+3=4Thus the new PE is,U = 2\1 k(x ′ ) 2

1 k(x ′ ) 2 = 2\1 k×4 ^2

2 = 2 /16

16K =16UChange in potential energy ΔU

=16U−U=15U

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Answer 2

Answer:

2.3 J

Explanation:

potential energy = 1/2 k x^2

=1/2 ×115N/m ×(0.200m)^2

=2.3N/m^2

=2.3 J