Question

A 1% aqueous solution of a substance is isotonic with 3% solution of glucose. The molar mass of the substance is





60 g



120 g



180 g



360

Answer 1

u have to solve this unitary method

Answer 2

Answer:

60

Explanation:

as they r isotonic...that means the conc. of both the solutions are the same..

so, C. of glucose = C. of non volatile substance.

3/180 = 1/x. (RMM of glucose = 180.

let RMM of substance be x)

x = 1 × 180 / 3

x = 60.