A(10,4), B(-4,9), C(-2,-1) are the vertices of a triangle. Find the equation of the altitude through B.
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A = (10,4). C (-2, -1)
Slope of AC = (4+1) / (10+2) = 5/12
Slope of BD or perpendicular from B onto AC : -12/5
B = (-4, 9)
equation of BD: (y - 9) / (x + 4) = -12/5
5 y - 45 = -12 x - 48
5 y + 12 x + 3 = 0
Slope of AC = (4+1) / (10+2) = 5/12
Slope of BD or perpendicular from B onto AC : -12/5
B = (-4, 9)
equation of BD: (y - 9) / (x + 4) = -12/5
5 y - 45 = -12 x - 48
5 y + 12 x + 3 = 0
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