Question

A 100 mL solution contains 0.0010 mol/L of calcium chloride and 0.0010 mol/L of
strontium chloride. 50 mL of 0.1000 mol/L sodium sulfate is added. Determine
the percentage by mass of calcium sulfate in the product. The solubility products
value of calcium sulfate is 9.1 x 10-6 and for strontium sulfate it is 3.2 x 107.​

Answer 1

Answer:

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Explanation:

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