Given 3 (log 5 - log 3) – (log 5 - 2 log 6) = 2 - log n, find n.
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Answer:
Given :
3(log5−log3)−(log5−2log6)=2−logn
Let us simplify the given expression to find n,
3log5−3log3−log5+2log6=2−logn
2log5−3log3+2log6=2(1)−logn
log5
2
−log3
3
+log6
2
=2log10−logn[Since,1=log10]
logn=−log25+log27−log36+log100
=(log100+log27)−log5+log36)
=log(100×27)−log(25×36)
=log(100×27)−log(25×36)
=log(100×27)/(25×36)
logn=log3
n=3
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