Question

(a^12+a^6b^6+b^12)/(a^6-a^3b^3+b^6)

Answer 1

ANSWER -

By using the law of exponents -


$= > ({a}^{12} + {a}^{6} {b}^{6} + {b}^{12}) \div ({a}^{6} - {a}^{3} {b}^{3} + {b}^{6 }) \\ \\ = > \frac{ ({a}^{12} + {a}^{6} {b}^{6} + b{}^{12})}{ ({a}^{6} - {a}^{3} b \: {}^{3} + b{}^{6}) } \\ \\ = > (\frac{ {x}^{2} }{ {x}^{2} } = 2 - 2) \: is \: a \: exponent \: rule \\ \\ = > {a}^{(12 - 6)} - {ab}^{(6 - 3)} + b{}^{(12 - 6)} \\ \\ = > {a}^{6} - {a}^{3} {b}^{3} + {b}^{6} \\ \\ = > So \: this \: is \: the \: required \\ \: answer$