Question

A 12 pole, 3ph alternator driven at a speed of 500 r. p. m supplies power to a 8 pole, 3ph induction motor. it the slip of the motor at full load is 3% then calculate the full load speed of the motor. ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

At the alternator the supply frequency,

f = (P×N)/120

=> (12×500)/120=50 Hz.

With the same frequency, Synchronous speed,

Ns = 120f/P

=> 120×50/8=750 r.p.m.

Since the slip % is 3%, the motor speed, N is

% slip, S = (Ns-N)/Ns ×100

3 => (750-N)/750 ×100

=> N = 727.5 r.p.m.