Math, asked by Debabratakarmakar, 1 year ago

A 15m long ladder reaches a window 12m high from the ground on placing it against a wall.How far is the foot of the ladder from the wall?

Answers

Answered by abhi569
577
By Pythagoras theorem,

(15)²=(12)²+distance ²

225=144+distance ²

225-144=81=distance²

√81=distance

9 = distance


Wall is far away from the ladder by 9 metre

I hope this much will help you
Answered by eudora
107

Given :

A 15m long ladder reaches a window 12m high from the ground on placing it against a wall.

To Find :

The distance between the ladder and wall on the ground.

Solution :

Let AB be the ladder and BC be the wall.

B is the position of the wall.

∵ the length of AB = 15 meter

and the length of BC = 12 meter

By Pythagoras Theorem :

In ΔABC, ∠C = 90°

(AB)² = (BC)² + (AC)²

(15)² = (12)² + (AC)²

AC² = 15² - 12²

AC² = 225 - 144

AC² = 81

AC = √81

AC = 9 meter

1 meter = 3.2808 foot

9 meter = 29.527 ≈ 29.53 foot

The distance of the ladder from the wall would be 29.53 foot or 9 meter.

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