Question

a 2.0 high object is placed perpendicular to the principle axis of a concave mirror. the distance of the object from mirror is 30cm, and its image is formed 60cm from the mirror, on same side of mirror as object.Find height of object

Answer 1

Object height (h1) = +2cm
object distance (u)= -30cm
image distance(v) = -60cm
image height (h) = ?

m = -v/u = h /h1

-v/u = h/h1

-(-60)/-30 = h/ -2

-2 = h/-2
4= h

h= 4cm

thus the height of the object = 4cm...
HOPE IT WILL HELP YOU

Answer 2

Explanation:

Explanation:

Image distance, v = -40cm

Focal length, f = -20cm

Object distance, u = ?

We know that,

1/u + 1/v = 1/f

=> 1/u = 1/f - 1/v

=> 1/u = 1/-20 - (1/-40)

=> 1/u = -1/20 + 1/40

=> 1/u = -2/40 + 1/40

=> 1/u = -1/40

=> u = -40 cm